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    Jakeman95's Avatar
    Jakeman95 Posts: 1, Reputation: 1
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    #1

    Oct 3, 2011, 09:34 AM
    Sec^-1 (- sqrt2)
    I need to find the exact value. I'm pretty lost.
    jcaron2's Avatar
    jcaron2 Posts: 986, Reputation: 204
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    #2

    Oct 3, 2011, 08:20 PM
    I'm assuming this means arcsec(-sqrt(2))?

    So this is essentially asking "What angle has a secant of -sqrt(2)?". If it has a secant of -sqrt(2), then (since secant = 1/cosine) it has a cosine of -1/sqrt(2), which is equal to -sqrt(2)/2.

    So what angle has a cosine of -sqrt(2)/2? I'm guessing you know the answer.
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