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    clueless123's Avatar
    clueless123 Posts: 6, Reputation: 1
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    #1

    Jul 12, 2008, 08:45 AM
    Rates of Change
    I'm unfamilar with this rates of change question.

    Let f be the function f:D -> R , f(x)=loge(3-4x) where D is the largest domain over which f is defined.

    Use calculus to show that the rate of change of f(x) with respect to x is always negative.

    I have no clue on how to do this, any help would be appreciated.
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Jul 12, 2008, 10:54 AM
    What do you mean by f(x)=loge(3-4x) ?



    Then, if you differentiate f(x) with respect to x, you'll find that the rate of change is always negative. You can substitute x in the differentiation by infinity and negative infinity to check your answer.
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