cody_10 Posts: 5, Reputation: 1 New Member #1 Nov 6, 2007, 04:48 PM
Can you hel pme solve this equation using the quadratic formula:

5X^2-2X+8=0

thank youuuuu!
 terryg752 Posts: 197, Reputation: 4 Junior Member #2 Nov 6, 2007, 08:18 PM
You can do it yourself by following the following:

Solutions of ax^2 + bx + c = 0

are [-b + (b^2 - 4ac)^1/2]/2a and [-b - (b^2 - 4ac)^1/2]/2a

I think your confusion may arise because both roots are complex numbers.

So remember that the square root of a negative number is imaginary, e.g.

(100)^-1/2 = I (100)^1/2 = 10 I

where I = square root of (-1)

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