How do I differentate ln(x + y) = y? I start with ' = ' ' + ' = y' I know ' = 1/x But I'm not sure what ' should be. I thought it was (1/y)y' (or y'/y), but I can't get to the answer, shown as:

Given x^2-y^2, find dy/dx by implicit differentiation

Use implicit differentiation to find y' ln(xy) = x+y Use implicit differentiation to find y' at (5,2) 3xy + 3x = 45 Find the differential dy given the following function if p and q are constants f(x) = x^p + x^q

Use implicit differentiation to find y' : xe^xy=y Use implicit differentiation to find y': xln y = y^3 - 2

The question is as follows: Recall that (x-h)^2 + (y-k)^2 = r^2. The circle's center is (h,k), with radius r. Show that the tangent (derivative) to is perpendicular to the radius at the point of tangency. Use implicit differentiation. If anyone could help me with that question...