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    skumar1st's Avatar
    skumar1st Posts: 4, Reputation: 1
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    #1

    Feb 18, 2014, 01:04 AM
    How this math answers came
    Unable to understand this calculation. How came "0.2881 + 0.1554"? Please explore
    P(12 < x < 15) = P(-0.8 < Z < 0.4)
    = P(-0.8 < Z < 0) + P(O < Z < 0.4)
    = P(O < Z < 0.8) + P(O < Z < 0.4)
    = 0.2881 + 0.1554 = 0.443
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Feb 18, 2014, 07:44 AM
    This problem is about finding the area under the normal distribution curve between Z=-0.8 and Z= 0.4. This is the same as finding the area from 0 to 0.8 plus the area from 0 to 0.4 -- do you understand why that is?
    skumar1st's Avatar
    skumar1st Posts: 4, Reputation: 1
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    #3

    Feb 19, 2014, 08:10 PM
    But how come 0.2881 and 0.1554?
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #4

    Feb 20, 2014, 05:32 AM
    You use a table of values for the area as a function of z-score. See for example:

    Attachment 45701

    Note that the value for z=0.8 is 0.2881, and the value for z=0.4 is 0.1554.

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