Ask Experts Questions for FREE Help !
Ask
    emmacorless's Avatar
    emmacorless Posts: 1, Reputation: 1
    New Member
    		  
    #1

    Jan 31, 2011, 08:56 PM
    how do you derive cos(sin(x^2-3x))
    find the derivative of cos(sin(x^2-3x))
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
    		  
    #2

    Jan 31, 2011, 10:27 PM

    When you have

    y = cos(f(x))

    The derivative is:

    y' = f'(x). -sin(f(x))

    Apply the same thing here, twice.







    Then you simplify if necessary.
Not your question? Ask your question View similar questions
 

Question Tools Search this Question
Search this Question:

Advanced Search

Add your answer here.


Check out some similar questions!

Solve the equation: cos^3(x) - sin^3(x) = cos^2(x) [ 1 Answers ]

Help, please :)

Evaluate the following: a. Sin(sin^-1(x) + cos^-1(y)) and [ 4 Answers ]

and b. cos(sin^-1(x) - cos^-1(y))

Verify identity (sin^3(x) cos^3(x)) /sin(x) cos(x) [ 4 Answers ]

= (csc^2(x) - cot(x) - 2cos^2(x))/1 - cot^2(x)

Verify identity (sin^3(x) +cos^3(x)) /sin(x)+cos(x) = 1-sin(x)cos(x) [ 2 Answers ]

I needd helppp. I can't verify this identity! Pleasee help and show full work. Thanks :)

[(sin x cos x)/ (csc x sec x)] = (sin x cos x) [ 1 Answers ]

I need help verifying this problem algebraically: (sin x + cos X)/(csc x + sec x) = sin x cos x

View more questions Search