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shreyas123 · May 30, 2009, 09:38 AM

(x-2)/(x-3)-(x-4)/(x-5)=10/3

Capuchin · May 30, 2009, 10:03 AM

Have you tried graphing it?

shreyas123 · May 30, 2009, 10:23 AM

Originally Posted by Capuchin

have you tried graphing it?

no... :rolleyes:i dit tried becoz we have to solve :rolleyes:this questiona algebrically... :D

galactus · May 30, 2009, 11:48 AM

$\frac{x-2}{x-3}-\frac{x-4}{x-5}=\frac{10}{3}$

Subtract it like any fraction. Find the common denominator, which is (x-3)(x-5).

Doing so, we get:

$3((x-5)(x-2)-(x-3)(x-4))=10(x-3)(x-5)$

$-6=10x^{2}-80x+150$

Now, finish?