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    lemon14's Avatar
    lemon14 Posts: 143, Reputation: 9
    Junior Member
     
    #1

    Oct 15, 2011, 03:01 AM
    Extreme values for f(x) = 3 cos3x - 4 sin3x - 2
    How to calculate the minimum and the maximum value of the function f(x) = 3 cos3x - 4 sin3x - 2 ?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Oct 15, 2011, 07:00 AM
    Find the derivative of the function, and then set the derivative to zero, solving for x.

    Or if you can do a sketch of the curve, you can already state the maximum and minimum values.

    Do you know how to do that?
    lemon14's Avatar
    lemon14 Posts: 143, Reputation: 9
    Junior Member
     
    #3

    Oct 15, 2011, 12:07 PM
    Well, not really.

    I haven't learnt about derivatives yet, so I guess the curve will help more.

    In this case, I can deal with it, I just didn't know this exercise required some other knowledge.

    Thank you very much.
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Oct 15, 2011, 12:37 PM
    Derivative is just the same as differentiation, okay :)

    Otherwise, to make drawing easier, you could change it like that



    If you know how to use that.

    Expand the right:


    Then, put B = 3x
    If you can understand what you're doing, I'm sure the graph will become easy. :)

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