dths1980 Posts: 11, Reputation: 1 New Member #1 Jun 26, 2008, 12:16 PM
evaluate the following integral
1. 32(x^2+1)^7 dx

in front to the bracket is the "s" like sign at the top is 1 and at the bottom 0

thank you
 galactus Posts: 2,271, Reputation: 282 Ultra Member #2 Jun 26, 2008, 12:53 PM
$32\int_{0}^{1}(x^{2}+1)^{7}dx$

One way is to just expand out and integrate term by term.

$(x^{2}+1)^{7}=x^{14}+7x^{12}+21x^{10}+35x^{8}+35x^ {6}+21x^{4}+7x^{2}+1$

There is a lot of them, but they are easy to integrate.

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