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    RhodesKL's Avatar
    RhodesKL Posts: 1, Reputation: 1
    New Member
     
    #1

    Oct 12, 2006, 06:44 PM
    Derivatives: Exponential and Logarithmic Functions
    Is there any easy way to find the derivative of an exponential or logarithmic function? Or can anyone explain it simply?
    LucyMcgoo's Avatar
    LucyMcgoo Posts: 27, Reputation: 3
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    #2

    Oct 12, 2006, 10:21 PM
    I say the ol' trusty scientific calculator!
    JOHNSMITH55's Avatar
    JOHNSMITH55 Posts: 1, Reputation: 1
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    #3

    Oct 19, 2006, 02:39 AM
    loge(f(x))
    the derivative is
    f'(x) divided by f(x)

    e^kx
    the derivative is
    ke^kx
    (the k is a constant and is the derivative of the part that the "e" is powered to


    Hope this helps:)
    s_cianci's Avatar
    s_cianci Posts: 5,472, Reputation: 760
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    #4

    Nov 1, 2006, 09:06 PM
    The derivative of an exponential function is proportional to itself and is the only type of function with that property. That said, [d/dx] a^u = (a^u)(Ln a)(du/dx), the proportionality constant being Ln a. If a is the natural base, which is e (Euhler's Number), then Ln e = 1 and [d/dx] e^u = (e^u)(du/dx). The derivative of a logarithmic function is its reciprocal, times the derivative of its argument, divided by the natural logarithm of the base. That is, [d/dx] log a u = (1/u)(du/dx)(1/(Ln a))
    ahmedgawi's Avatar
    ahmedgawi Posts: 1, Reputation: 1
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    #5

    Mar 14, 2014, 04:51 AM
    y=C.e^ax

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