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Muhammad Ali Ni Posts: 10, Reputation: 1

New Member

#1

Jun 10, 2015, 02:10 AM

Derivative

dp/p+dv/v=(1-r)dv/v
its next step is
dp/p+rdv/v=0
can you please tell me urgently that how zero come in rhs??

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ebaines Posts: 12,131, Reputation: 1307

Expert

#2

Jun 10, 2015, 05:34 AM

Simply subtract (1-r)dv/v from both sides of the equation:

$\frac {dp}p + \frac {dv} v -(1-r) \frac {dv}v = (1-r)\frac {dv}v - (1-r) \frac {dv} v$

$\frac {dp} p + \frac {dv} v -\frac {dv}v + r \frac {dv} v = 0$

$\frac {dp} p + r \frac {dv} v = 0$

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