Ask Experts Questions for FREE Help !
    361fnc's Avatar
    361fnc Posts: 1, Reputation: 1
    New Member

    Sep 7, 2004, 02:59 PM
    Converting an equation
    I have an equation that has to do with weirs and flow rates, Q=288.8LH^(3/2) where Q is the discharge rate (gal/hr), L is the opening lenth (inches), and H is the height of the fluid (inches). How do I find a new constant if I where to change Q to (cubic feet/sec.) and L and H to feet? Thank you for your time.
    reinsuranc's Avatar
    reinsuranc Posts: 92, Reputation: 6
    Junior Member

    Feb 14, 2005, 12:14 PM
    I get 15591.22
    Q gallon/hour = 288.8 * (L inches) * ((H inches)^1.5)

    1 gallon = .13368 cubic feet (see
    1 hour = 3600 seconds
    1 foot = 12 inches

    Q * .13368 cubic feet/3600 seconds = 288.8 * ((L/12) feet) * ((H/12) feet)^1.5

    Q = (3600/.13368) * (288.8/12) * ((1/12)^1.5) * L * (H^1.5)

    Q = 15591.22 * L * (H^1.5)

Not your question? Ask your question View similar questions


Question Tools Search this Question
Search this Question:

Advanced Search

Add your answer here.

Check out some similar questions!

Nonlinear Systems of Equation [ 2 Answers ]

Nonlinear Systems of Equation: Problem: y = x^2 3x = y +2 Any assistance you can give me will greatly appreciated. Thank you!:)

Balance Sheet Equation [ 3 Answers ]

Revenues A Expenses 200 Dividends Declared 5 Additional Inv. 40 Net Income 20 Retained Earnings Beginning of Year 60 End of Year B

Basic equation help! [ 3 Answers ]

I have the answer on my paper but I can't figure out how to do the problem itself a c -(2x - 12)= - b d its 'a' over 'b' times 2x minus 12 equals 'c' over 'd'

Setting up equation? [ 2 Answers ]

I can not get how to form a formula or equation for this question. I don't want the answer I just need help getting it started. Thanks Jim can mow Mr.Smith's lawn in 6 hours, Bob can mow Mr.Smith's lawn in 4 hours. How long would it take them to mow the yard if they worked together?

View more questions Search