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    MartinBrits's Avatar
    MartinBrits Posts: 2, Reputation: 1
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    #1

    Feb 10, 2015, 10:53 AM
    Calculus question
    An oil spill on the open sea in calm weather spreads in a circular pattern. If the radius of the oil spill increases at the rate of 0.9m/s, how fast is the area of the spill increasing when its radius is 225?
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Feb 10, 2015, 10:56 AM
    You do know the formula for the area of a circle, right? You're looking to take its derivative with respect to time - try it and post back with what you get.
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    MartinBrits Posts: 2, Reputation: 1
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    #3

    Feb 11, 2015, 09:52 AM
    @ EBAINES.Please verify my method below.A=πrēdr/dt = 0.9m/sr = 225mdA/dt = 2πr(dr/dt)dA/dt = 2π(225)(0.9)dA/dt = 1272mē/sThanks in advance

    @ EBAINES


    A=πrē
    dr/dt = 0.9m/s
    r = 225m


    dA/dt = 2πr(dr/dt)
    dA/dt = 2π(225)(0.9)
    dA/dt = 1272mē/s


    Thanks in advance
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    ebaines Posts: 12,131, Reputation: 1307
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    #4

    Feb 11, 2015, 11:34 AM
    Quote Originally Posted by MartinBrits
    dA/dt = 1272mē/s

    Correct!
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