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    VolsFan89's Avatar
    VolsFan89 Posts: 1, Reputation: 1
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    #1

    Jan 28, 2008, 12:59 PM
    Addition Using Exponents
    (-2)^4 + (3)^-1=??
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Jan 28, 2008, 01:08 PM
    Which part are you having touble with? Can you evaluate (-2)^4? As for 3^-1, that is the inverse of 3^1 , that is, 1/(3^1). Then just add the two parts.
    jiten55's Avatar
    jiten55 Posts: 105, Reputation: 8
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    #3

    Jan 28, 2008, 04:15 PM
    Here are some examples to help you:

    (-3)^4 = 3^4 (raising to an even power makes it positive)

    = 3*3*3*3 = 81

    (4)^-1 = 1/(4^1) = 1/4
    ellyjane's Avatar
    ellyjane Posts: 1, Reputation: 1
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    #4

    Jul 3, 2012, 08:55 AM
    my question is 6.42X10^8+4.12X10^7
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #5

    Jul 3, 2012, 09:01 AM
    Adding these requires converting the 4.12 x 10^7 number into the equivalent using 10^8. Do you know how to do that? Then you can simply add. Here's an example that shows how to do this: consider 6.5 x 10^5 + 3.2 x 10^4. Change 3.2 x 10^4 to 0.32 x 10^5. Now you have 6.5+10^5 + 0.32 x 10^5 = (6.5 + 0.32) x 10^5 = 6.82 x 10^5. Hope this is clear.
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