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    Sarah_Marie's Avatar
    Sarah_Marie Posts: 24, Reputation: 1
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    #1

    Oct 13, 2010, 08:03 AM
    What is the sum of twice a number and three times its square of 261.
    How would I calculate this question?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Oct 13, 2010, 08:26 AM

    Is that the original question? Because I can't make head or tail of it... :confused:
    olderexgeek's Avatar
    olderexgeek Posts: 9, Reputation: 1
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    #3

    Oct 13, 2010, 03:02 PM
    the sum is equal to 2x + 261 is one possible guess as to what you're asking
    261 = 3X squared or X squared = 261... then the equation might be 2x + 3(261) or it might be 261 is the square root of x
    all yield different results
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Oct 13, 2010, 09:43 PM

    Could it be:

    Sum of twice a number, added to thrice its square yielding 261?

    If so, we can let the number be y.

    Then, twice that number becomes 2y, thrice it's square becomes 3y^2.

    Or,





    Solve the quadratic to get the two possible values of the number.
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