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    dontletmego's Avatar
    dontletmego Posts: 22, Reputation: 1
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    #1

    Oct 19, 2012, 11:25 AM
    What is the result of the sum taking in consideration the function:

    ZacheryA's Avatar
    ZacheryA Posts: 20, Reputation: 1
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    #2

    Oct 19, 2012, 12:55 PM
    I think you might have made a typo don't you mean f(0)+f(1)+f(2) etc?
    ZacheryA's Avatar
    ZacheryA Posts: 20, Reputation: 1
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    #3

    Oct 19, 2012, 12:57 PM
    Algebra isn't that hard all you have to do for every f(#) is replace the x by the #. For example f(x)=5x-1 ->
    f(0)=5*0-1=-1
    f(1)=5*1-1=5-1=4

    Now go do your homework, lol
    dontletmego's Avatar
    dontletmego Posts: 22, Reputation: 1
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    #4

    Oct 22, 2012, 05:41 AM
    Quote Originally Posted by ZacheryA View Post
    I think you might have made a typo don't you mean f(0)+f(1)+f(2) etc?
    Quote Originally Posted by ZacheryA View Post
    Algebra isn't that hard all you have to do for every f(#) is replace the x by the #. For example f(x)=5x-1 ->
    f(0)=5*0-1=-1
    f(1)=5*1-1=5-1=4

    Now go do your homework, lol
    No, there are no mistakes in the enuciation of the problem.

    If it had been just a sum, I wouldn't have been asked for some tips because it's obvious that the solution would have been S = 5 (1 + 2 + 3 +... + 50) + 51 = 5 (50 * 51) / 2 + 51 = etc. but in this case it looks like S = 5 (-1 + 2 - 3 + 4 -5 +... + 50) + k * 1. So how could I solve for this?
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #5

    Oct 22, 2012, 07:50 AM
    Hint: consider that the sum of f(n) - f(n+1) always equals -5 for any even value of 'n.' Can you take it from here?
    dontletmego's Avatar
    dontletmego Posts: 22, Reputation: 1
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    #6

    Oct 22, 2012, 08:52 AM
    Quote Originally Posted by ebaines View Post
    Hint: consider that the sum of f(n) - f(n+1) always equals -5 for any even value of 'n.' Can you take it from here?
    Thank you a lot !
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