danyzavala Posts: 5, Reputation: 1 New Member #1 May 18, 2009, 02:41 PM
What is the new value of the temperature?
A balloon having an initial temperature of 16.4°C is heated so that the volume doubles while the pressure is kept fixed. What is the new value of the temperature?
 Perito Posts: 3,139, Reputation: 150 Ultra Member #2 May 18, 2009, 02:58 PM

The general P,V,T equation (Boyles' + Charles' laws) can be written:

$\frac {P_1V_1}{T_1} = \frac {P_2V_2}{T_2}$

In this case P1=P2 so this simplifies to

$\frac {V_1}{T_1} = \frac {V_2}{T_2}$

Plug in the temperature (must be in Kelvins or Rankines -- the absolute temperature scale). You know that V2 = 2*V1 so replace V2 with that and solve for T2

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