joven Posts: 1, Reputation: 1 New Member #1 Sep 8, 2010, 03:27 AM
The sum of the digits of a two-digit number is 9. the tens digit is 3 less than the
Square of the units digit. Find the number.
 ebaines Posts: 12,131, Reputation: 1307 Expert #2 Sep 8, 2010, 08:59 AM
You ned to set this problemn up as two equations in two unknowns. Let's call the tens digit 'A', and the units digit 'B'. You know that:

A + B = 9 (since the sum of the tens digit and units digit is 9)
A = B^2-3 (since the tenbs digit is 3 less than the square of the units digit)

Yo can now rearrange the first equation to get A by utself, then substitute that equation for A into the second equation. At this point you'll have one equation for B, which will be a quadratic that you can factor to determine B. Then finally substitute that value for B back into the first equation to figure out what A is. Good luck, and post back with what you get for a final answer.

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