FARLEYcommak Posts: 1, Reputation: 1 New Member #1 May 21, 2008, 07:48 PM
Statistics homework!
Okay, here is the problem I'm stuck on

The heights of women aged 20 to 29 follow approximately the N(64, 2.7) distribution. Men the same age have heights distributed as N(69.3,2.8). What percent of young men are shorter than the mean height of young women?

I have been trying to figure out where to even begin and I have no clue! If someone can show me how to solve this that would be great!!
 ebaines Posts: 12,132, Reputation: 1307 Expert #2 May 22, 2008, 09:16 AM
You know that the mean height of women in this sample is 64. To determine what percentage of men who are shorter than that, you first o determine what the z-score is for men whse heihgt is 64. Z-score is found from:

$
z = \frac {x - \mu} \sigma = \frac {64-69.3} {2.8} = -1.9
$

So now you look up the percentage of the normal distribution that is 1.9 standard deviations or more from the mean. Hope this helps.

 Question Tools Search this Question Search this Question: Advanced Search

## Check out some similar questions!

I'm sorry! I can not find anywhere to post my question about Statistics, so I decided to post this in Accounting! If this is not suitable for this Box, please let me know. My question is about constructing a Box-Whisker Plot in Statistics. How do we draw whiskers when the Mean is outside the Box...

12) A metropolitan bus system sampler's rider counts on one of its express commuter routes for a week. Use the following data to establish whether rider ship is evenly balanced by day of the week. Let = 0.05. Day Monday Tuesday Wednesday Thursday Friday Rider 10 34 21 57 ...