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    smileysrd's Avatar
    smileysrd Posts: 6, Reputation: 1
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    #1

    Sep 18, 2010, 09:18 AM
    statistics help
    standard deviation, the probability is 0.20 and value greater than 79.2. normal distribution with mean of 62.4.
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Sep 18, 2010, 09:21 AM

    Well, what you know:



    Then, P(X>79.2) = 0.2

    1. Find the z value that corresponds to this probability.

    2. Use to find the value of the standard deviation.

    Post what you get! :)
    smileysrd's Avatar
    smileysrd Posts: 6, Reputation: 1
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    #3

    Sep 18, 2010, 08:16 PM
    statistics help
    When using the z score equation and you know the mean and standard deviation, but how do you figure out the X. Is x the mode or median?
    smileysrd's Avatar
    smileysrd Posts: 6, Reputation: 1
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    #4

    Sep 18, 2010, 08:18 PM
    statistics help
    when you have the probability and the mean, how do u figure out the standard deviation and the z score. Mean is 47.3. probability is 0.25.
    morgaine300's Avatar
    morgaine300 Posts: 6,561, Reputation: 276
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    #5

    Sep 18, 2010, 09:25 PM

    You've posted this question like 4 times now. Could you please stop as it just confuses everyone.
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #6

    Sep 19, 2010, 06:34 AM

    I'll give you an example. Try to work your questions and post what you did before asking a question next time.

    Qu. The heights of female students at a particular college are normally distributed with a mean of 169 cm and a standard deviation of 9 cm.
    (a) Given that 80% of these female students have a height less than h cm, find the value of h.
    (b) Given that 60% of these female students have a height greater than s cm, find the value of s.

    Solution:
    Let X represent the height, in centimetres, of a female student.



    (a) Given

    Standardising;



    Let



    The corresponding z value in your table for this probability is 0.842

    Hence,



    So,

    (b) Given

    Standardising;



    Let



    But if you made a sketch of the normal table and shaded the right area, you'll see that z must be negative.

    This z value corresponding to the probability is given by -0.253 in your table.

    Hence



    So,

    Questions? :)

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