



Junior Member


Jan 17, 2008, 11:00 AM


Are of square, inside of a circle
A square is inscribed in a circle of radius 3(square root sign)2. Find the area of the square.
First off, Idk how to put a square root symbol up on this question haha.
Second, I get the radius. I just did 18x3.14
But I don't know how to get the area of the square if the only measurement given is the radius of the circle. :eek:



Uber Member


Jan 17, 2008, 12:29 PM


The radius of the circle is equal to half the diagonal of the square. Use trigonometry to find the length of the side of the square. From there it's easy. Or you canjust use the area of a triangle once you have the length of the diagonal.



Junior Member


Jan 17, 2008, 01:32 PM


So the diagonal of this square is 6?



Uber Member


Jan 17, 2008, 01:44 PM


no it's



Senior Member


Jan 17, 2008, 01:59 PM


pythagorean
A squared + B squared = C squared
C = 6,square root of 2
figure it out from there



New Member


Jul 29, 2008, 02:49 AM


I do agree with this answer and it is absolutely right answer.
_________________________
Antra
Wide Circles



New Member


Jul 30, 2008, 02:20 AM


The problem is interesting. I tried to solve it. But I got confused that whether the diagonal has any relationship with the side of the square. So if you try to solve this I may proceed with the problem.

Bert
Wide Circles



Uber Member


Aug 2, 2008, 03:11 AM


Or, without the pythagoras theorem... a square is composed of two triangles if you cut it through the diagonal, in two. You have the base, , and perpendicular height. Using half base times height, you get one triangle, and multiplying by two, you have the area of the square.
Or simpler, if you 'mix' the two steps, you have the area of the square as: diameter of circle x radius of circle.



New Member


Jul 30, 2010, 02:53 AM


A square is inscribed in a circle of radius 3(square root sign)2. Find the area of the square.
radius r = 3√2
using the trigonometry you can find out the area of square as following:
for squares,
a² + b² = c²
but a = b (for squares)
so 2a² = c²
but c = 2r
so 2a² = (2r)²
so a² = 2r²
but r = 3√2
so a² = 36.



Ultra Member


Jul 30, 2010, 05:18 AM


Why would you answer a question that is 2 years old? It is likely a moot point by now.



New Member


Dec 15, 2010, 08:37 AM


galactus  I was searching for help with a similar problem when I came across this forum so I'm glad that kinjalpanwala answered a 2 year old question!



New Member


Oct 1, 2011, 09:01 AM


Well, galactus, since my son has the same question TODAY, it's not moot to me! 8) His question is: the area of the square is 50, what's the area of the circle? We get 12.5 times pi, but the book says it's 25 times pi.



Uber Member


Oct 1, 2011, 10:46 AM


twingleton, just start another thread to ask your question please.
But as it is your first time here, I'll try to help you.
The area of the square is 50, the length of one side is therefore
The radius of the circle is then
This agrees with your answer. Or maybe your misread the question?
If the square is inscribed inside the circle instead of the other way round, then, you have the radius of the circle as
And there goes the 25pi.



New Member


Oct 26, 2011, 08:33 AM


This page was helpful in solving the problem even though 2 years old.
A REAL practical application: I have a container with a diameter of 2.5" used to etch a circuit board. What is the maximum size of square circuit board that I can fit into the container? (1.78")



Uber Member


Oct 26, 2011, 08:48 AM


Is the height 1.78"?
If so, you already have know that the square board will have to have a length of 1.78" or shorter. The diameter is even larger that that, so I see no problem for the board to fit in, nor the need to bend the board.


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