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    wardas's Avatar
    wardas Posts: 3, Reputation: 1
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    #1

    Nov 27, 2009, 09:13 AM
    solving for 3 variables
    A theatre has 700 seats. The orchestra seats sell for $40 each, the main seats sell for $25 each, and the balcony seats seel for $20 each. When all orchestra, main, and balcony seats are sold, the theatre collects $18,450. When half the orchestra seats and all the main and balcony seats sell, then the theatre collects 15,650. How many orchestra, main, and balcony seats are available?
    I definitely have attempted this. I am coming up in circles. I solved for o(orchestra) first to come up with o = 700 -m -b. Then I substituted o with the above equation to solve for b (trying to get the equation into two variables). My answer came to b=477.5 - .75m. Then, I solved for m (main seats) which came to m = 839.58. I AM LOST since there are only 700 seats to begin with (m cannot possibly be 839.58).
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #2

    Nov 27, 2009, 12:49 PM

    See here:

    https://www.askmehelpdesk.com/mathem...es-419757.html

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