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 Can someone explain to be the concepts and procedure to solving something like the following question? (I) log4 2 ! Log9 (2x ! 5) # log8 64 
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 So, here's another question that I am having trouble with: - log(5)y = 2 I followed the steps that were used in a sample question just like this one and I still got the wrong answer... or I just don't know how to finish it. Here's what I've done: (2/log(5)3) * log(5)x = 2 + log(5)y ... 
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 Here is the question I have to answer: 5log(2)y – log(2)x = 3log(2)4 + log(2)a (I'm sorry if this is not written properly. I'm not sure how to do subscript typing for the 2s.) This is what I've come up with: log(2)y^{5} = 3log(2)2^{2} + log(2)a + log(2)x log(2)y^{5} = 3log(2)2^{2} +... View more questions Search 
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