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    lookywaticando's Avatar
    lookywaticando Posts: 4, Reputation: 1
    New Member
     
    #1

    Feb 11, 2008, 06:44 PM
    solve for the specified variable
    OK so I have looked this up and still have yet to figure out remotely even how to do this problem

    problem: A=2(wl+wh+lh) solve for w (surface area of a rectangular box)
    JBeaucaire's Avatar
    JBeaucaire Posts: 5,426, Reputation: 997
    Software Expert
     
    #2

    Feb 11, 2008, 07:30 PM
    A box has 3 dimensions

    Height
    Length
    Width

    If Height = 4, Length = 5 and Width = 3, then use that to complete your own formula:

    A=2(wl+wh+lh)
    A=2((3*5) + (3*4) + (5*4))
    A=2(15+12+20)
    A=2(47)
    A=94

    Now that you understand the process, you can figure out any one of the dimensions if you know the other 3, If you know AREA & WIDTH & LENGTH, you can use algebra to work backwards and figure out the HEIGHT.
    nesha123's Avatar
    nesha123 Posts: 2, Reputation: 1
    New Member
     
    #3

    Jan 2, 2011, 09:16 PM
    p=2(l+w)

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