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    cool_dude's Avatar
    cool_dude Posts: 124, Reputation: 9
    Junior Member

    Jan 9, 2007, 04:03 PM
    Solubility of Calcium Hydroxide
    Hi I am a grade 12 student and this is my first time posting a question here and hope someone can help out. The unit I am studying right now is chemical systems in equilibrium and I cannot answer one of the questions. If someone can help out that would be great

    If 10.02 mL of 0.100 mol/L hydrochloric acid is required to neutralize 25.00 mL of a saturated calcium hydroxide solution. What is the concentration of the hydroxide ions present? What is the solubility of calcium hydroxide in mol/L?

    Thanks in advance
    RickJ's Avatar
    RickJ Posts: 7,762, Reputation: 864
    Uber Member

    Jan 9, 2007, 04:15 PM
    Welcome, cool_dude. I'll move this to homework help where it will be better received. Good luck with it!
    cool_dude's Avatar
    cool_dude Posts: 124, Reputation: 9
    Junior Member

    Jan 9, 2007, 06:35 PM
    I think I got the answer but I'm not 100% sure. I got 0.02004 M for the first part of the question which is the concentration of hydroxide ions. I still need help with the second part of the question

    Can anyone please check my answer and maybe show me another way of doing this problem.

    Thank you
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
    Uber Member

    Jan 10, 2007, 12:48 AM
    So you have 1.002 mmol of H+ which will neutralise the same amount of OH-.

    So the concentration of OH- is 1.002 mmol in 25 ml which is 0.04008 mol/l

    As the formula for Calcium hydroxide is Ca(OH)2 you must have half as many moles of Ca(OH)2, i.e.. 0.501 mmol.

    As the solution is saturated, we can argue that it is at the solubility limit, thus the solubility is given by:

    0.501 mmol in 25 ml which is 0.02004 mol/l

    Does that make sense? I'd like others to check and make sure I got it right, I'm a little rusty on this chemistry malarky :)
    cool_dude's Avatar
    cool_dude Posts: 124, Reputation: 9
    Junior Member

    Jan 10, 2007, 12:56 PM
    Thank you very much for the explanation. My teacher finally came back so I asked her to explain and yes my answer and your answer are correct.

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