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What is the magnitude and direction of the force A
What is the magnitude and direction of the force A so that the system of concurrent forces shown is in equilibrium?
What steps to I need to know to solve this problem. I am stuck! <img src="http://i66.tinypic.com/2wf0qip.jpg"> |
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The thread you cited is not exactly the same problem, but it's close. Using that technique you can determine the resultant force in the x- and y- directions due to the addition of the two given forces, and then the force A would be the opposite of that, so that it cancels out the resultant. Or stated another way: you can add the negatives of the two given forces, and that will give you force A. Try it, and post back with what you get for an answer.
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Start with the 50K N force - do you know how to break that force into x- and y-components? The do the same for the 40K N force. Then add the two x-components to get a total x-value, and add the two y-components to get the total y value. That tells you that the values for the x- and y- components of force A, which must be pointed in the opposite directions (so that all the forces cancel).
Show us your work for each step, and we'll check it for you. |
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