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    Skeleuth's Avatar
    Skeleuth Posts: 1, Reputation: 1
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    #1

    Apr 24, 2012, 07:06 PM
    How do you show that the equations are equal?
    How do you show that the equations are equal?

    (tan^2(x))/csc(x) + 1 = tan^4(x)*(csc(x)-1)
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Apr 25, 2012, 05:47 AM
    Quote Originally Posted by Skeleuth View Post
    How do you show that the equations are equal?

    (tan^2(x))/csc(x) + 1 = tan^4(x)*(csc(x)-1)
    Actually as writtem these are not equal - because you left out a set of parentheses. I think what you want to show is:

    tan^2(x)/(csc(x) + 1) = tan^4(x)*(csc(x)-1)

    Start by multiplying both sides by csc(x)+1. You will end up with a term of the form csc^2x-1 on the right side, which can be simplified to 1/tan^2x.
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