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    jhunt's Avatar
    jhunt Posts: 1, Reputation: 1
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    #1

    Oct 18, 2011, 08:52 PM
    can you help us find out how to solve the problem ?
    f(x) 15x-2/x; f(a)=1 this is such a weird problem we don't under stand the steps requiered to find the answer
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Oct 19, 2011, 07:32 AM
    Given f(x) = 15x-2/x, the problem is asking you to find value(s) of 'a' such that f(a)=1. So you need to solve:

    15a - 2/a = 1

    You can multiply through by 'a' and rearrange to get a quadratic equation, then use the quadratic formula to find the two values for 'a' that satisfy this.
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