[jonahnaks13]

Like: the cubed root of 40n exponent 4... please.:D

[DanaJena]

I think the answer is 2n cube root of 5n

[EuRa]

You break down the inside of the root, then take out the sets you need. I'll take your example.

³√(40n^4)

First you break down the 40 if you can. You have to break 40 down as much as possible (dividing it by prime numbers), to find out if there are 3 of the same number that go into it. 40 broken down all the way is:

2 * 2 * 5 * 2 = 40. So as you can see, 2 goes into 40 three times, so you can pull the 2 out, and leave the 5. Then you have to break down the n^4, which is simply:

n * n * n * n = n^4. So you can take an "n" out, and that leaves one n.

Then you put the problem back together. The 2 and an "n" are on the outside, and a 5 and an "n" are left on the inside:

2n√(5n)


Once you get good at it, you can see the numbers that come out a lot easier.