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math10 · Jun 14, 2008, 10:33 AM

I'm stuck can anyone please help with the following math question - I'm studying for exams

y-2 over 3 + y-1 over 5 = 2
under
x+2 over 7 - y+5 over 3 = -2

galactus · Jun 14, 2008, 11:17 AM

Could you please post so we can be sure of what you mean. Come on, it's easy to write

(y-2)/3+(y-1)/5=2, assuming that is what you mean? I am not trying to be critical, but it makes your problem rather ambiguous to translate.

Assuming I am correct in my translation:

Solve for y, $\frac{y-2}{3}+\frac{y-1}{5}=2$

The LCD is 15, so multiply through by 15:

$\not{15}^{5}\cdot\frac{y-2}{\not{3}^{1}}+\not{15}^{3}\cdot\frac{y-1}{\not{5}^{1}}=15\cdot{2}$

$5(y-2)+3(y-1)=30$

$5y-10+3y-3=30$

Can you finish? Let me know if you remain stuck.

You treat these as you would any fraction. Find the LCD first. Does that help?