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    sarabear414 Posts: 1, Reputation: 1
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    #1

    Oct 24, 2007, 06:22 AM
    College Algebra
    If f(x)= 3x^2 +7 Then how do you solve f(2x+3)?
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    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Oct 24, 2007, 06:26 AM
    Simply plug "2x+3" in place of the "x" in f(x) = 3x^2+7. You get: f(2x+3) = 3(2x+3)^2+7. You can take it from there and simplify.
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