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    math_dude16's Avatar
    math_dude16 Posts: 19, Reputation: 1
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    #1

    Mar 13, 2009, 08:59 AM
    Saxon Algebra
    Please help me:
    Use Nn as the variable for the number of nickels and Nd as the variable for the numbler of dimes to write two equations that correspond to the following statement and solve for the Nn and Nd:

    The number of nickels exceeds the number of dimes by 7. The total value of the coins is $1.55.
    KISS's Avatar
    KISS Posts: 12,510, Reputation: 839
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    #2

    Mar 13, 2009, 09:02 AM

    Nn+7=Nd

    The other eqn is way too easy. "exceeds" just means +
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    math_dude16 Posts: 19, Reputation: 1
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    #3

    Mar 13, 2009, 09:10 AM

    I know I used that equation but my answer was WHACKO!
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    Capuchin Posts: 5,255, Reputation: 656
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    #4

    Mar 13, 2009, 09:33 AM

    The first equation should be Nn = Nd + 7

    maybe this is where you went wrong? We can't help you unless you give us your working, so we can see where you went wrong.
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    KISS Posts: 12,510, Reputation: 839
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    #5

    Mar 13, 2009, 09:36 AM

    Capuchin:

    Your right as always.
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    math_dude16 Posts: 19, Reputation: 1
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    #6

    Mar 13, 2009, 09:38 AM

    well this is what I have so far:

    Nn=ND + 7
    Nn+ND=1.55

    ND+ND+7=1.55
    2ND+7=1.55
    But now it doesn't make sense because the answer would be negative is that right:?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #7

    Mar 13, 2009, 09:49 AM

    Your second equation should be Nn*5 + Nd*10 = 155
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    math_dude16 Posts: 19, Reputation: 1
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    #8

    Mar 13, 2009, 09:51 AM

    Wait what?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #9

    Mar 13, 2009, 10:09 AM

    The number of nickels* 5cents + the number of dimes * 10cents = 155 cents

    It's not the number of coins that = 1.55, it's the value of the coins, which you hhavent accounted for.
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    math_dude16 Posts: 19, Reputation: 1
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    #10

    Mar 13, 2009, 10:11 AM

    Oh man I feel so stupid how could I miSS tHAT! Thanks so much!
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