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    SlyPhoenix's Avatar
    SlyPhoenix Posts: 63, Reputation: 2
    Junior Member
    		  
    #1

    Apr 6, 2009, 07:49 AM
    Reaction Equilibriums
    Using this reversible reaction, answer:
    N2O4 2NO2

    If the change of enthalpy of this reaction when proceeding left to right is 14Kcal,
    what is the correct chemical equation?


    N2O4 = 2NO2 + 14 kcal
    N2O2 = 2NO2, HR = +14 kcal
    N2O4 + 14 kcal = 2NO2
    N2O4 = 2NO2, HR = -14 kcal
    .

    I think it is the 4th one. Am I right?
    Perito's Avatar
    Perito Posts: 3,139, Reputation: 150
    Ultra Member
    		  
    #2

    Apr 6, 2009, 04:56 PM

    The first equation is usually how it is written when heat is released, as in this case.
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