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    little_emo_emily1437's Avatar
    little_emo_emily1437 Posts: 2, Reputation: 1
    New Member
     
    #1

    Dec 13, 2006, 09:08 PM
    Rate-Time-Distance problem.. help!

    I don't get his "Rate-Time-Distance" Problem given to me... it's confusing to me!:confused:
    :eek: HELP!:eek: Can you show me how to do it?? :D

    Here's the problem... :)



    At. 7:00 am Mr. Van starts jogging at 6 mi/h. At 7:10 am you start after him along the same path. How fast must you run to catch Mr. Van at 7:30 am?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #2

    Dec 14, 2006, 03:56 AM
    How far does he go in the first 10 minutes? How fast do you have to go to go that distance in 20 minutes? How much faster than him do you have to go to be going the same speed as him but a little extra to go the distance he has already gone in 20 minutes. How fast must you go?

    Hopefully this will help you think about the problem in a better way
    asterisk_man's Avatar
    asterisk_man Posts: 476, Reputation: 32
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    #3

    Dec 14, 2006, 07:37 AM
    Oooh. I almost wrote my own explanation of how to do the problem but then I realized that would probably be like giving the answer away. Bad asterisk!

    I'm happy with the way you wrote it capuchin. A little info, but not explicitly spelling it out. This is definitely a homework problem and that's definitely the way to go!

    Way to follow the rules capuchin!!
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #4

    Dec 14, 2006, 07:45 AM
    Thanks asterisk

    Lilemily please see this link, the question is basically the same as yours but with different numbers, I posted similar hints but possibly in a clearer manner. It may help

    https://www.askmehelpdesk.com/math-s...lem-47690.html
    Hannii's Avatar
    Hannii Posts: 1, Reputation: 1
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    #5

    Jan 17, 2008, 02:51 PM
    Mr. Van ---------------> (7:00) (6mi)
    you--------------------> (7:10) (x mi)

    Rate X Time = Distance
    Mr. Van rate =6 time=1/2 D= 3
    you rate= x time= 1/3 D=1/3
    1/3x = 3
    x = 9

    You ran 9mi/h

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