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    alyssamae07's Avatar
    alyssamae07 Posts: 7, Reputation: 1
    New Member
     
    #1

    Jul 21, 2012, 06:38 PM
    problem solving quadratic equations
    the length of a rectangle is 16 cm greater than its width. The area is 35 m^2. find the dimension of the rectangle, to the nearest hundreth of a metre.


    please help e I don't know what to do
    ArcSine's Avatar
    ArcSine Posts: 969, Reputation: 106
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    #2

    Jul 22, 2012, 05:25 AM
    Here you're given two facts about the situation, which can be expressed as

    L = W + 16

    L • W = 350,000

    ... where L and W represent the rectangle's length and width, respectively. (Since L and W are given in terms of cm, we're putting the rectangle's area into the same terms, recognizing that 1 m^2 = 10,000 cm^2.)

    Since the first one says that "W + 16" is just another way of saying "L", we can use this fact as a substitution in the second one, so that the second one becomes an equation in just one variable

    (W + 16) • W = 350,000

    From here, expand out the left-hand side, then deduct 350K from both sides to produce a quadratic equation in standard form. Then, as with your baseball-distance question, use the quadratic formula to determine W.

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