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    suzette1202's Avatar
    suzette1202 Posts: 7, Reputation: 1
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    #1

    Apr 15, 2008, 01:24 PM
    Probability in face cards
    Remove the Red cards from the deck and assume that the remaining card have been shuffled.

    Select a card from the remaining deck, Do Not replace the card. Select another card. What is the probability that a red 3 is selected and a face3 card is selected?
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Apr 15, 2008, 02:02 PM
    Is this a trick? After you remove the red cards from the deck there are only black cards left over, so the probability of pulling a red 3 from the remaining deck is obvioulsy 0. And what's a "face3" card?
    suzette1202's Avatar
    suzette1202 Posts: 7, Reputation: 1
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    #3

    Apr 15, 2008, 07:57 PM
    No this is a question on one of my assignments except that there is a typo on the face3. The 3 was a mistake, everythingelse is how it was given to me. I am very confused about it. It doesn't make sense to me either. I know that there are no red threes so why are they asking it that way and how do I get an answer? Thanks.
    ballengerb1's Avatar
    ballengerb1 Posts: 27,378, Reputation: 2280
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    #4

    Apr 15, 2008, 08:18 PM
    Suzette, do you know that there is a place for homeowkr questions? If there is a typo then you can't get an answer since you don't know how the question was supposed to read.
    suzette1202's Avatar
    suzette1202 Posts: 7, Reputation: 1
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    #5

    Apr 15, 2008, 08:36 PM
    No, I made the typo. Everything else is correct. I just don't know how to do this.

    Thanks
    ballengerb1's Avatar
    ballengerb1 Posts: 27,378, Reputation: 2280
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    #6

    Apr 16, 2008, 06:39 AM
    https://www.askmehelpdesk.com/homework-help/ Maybe you can get additional help here. PS you can correct your own typos within 24 hours of posting. See EDIT right next to the yellow box RATE THIS ANSWER.
    suzette1202's Avatar
    suzette1202 Posts: 7, Reputation: 1
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    #7

    Apr 16, 2008, 09:35 AM
    Thanks for the edit info but can we focus on the math problem? I need help. Thank you for all you can do to help me.
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #8

    Apr 16, 2008, 10:01 AM
    I agree with ebaines. How are you to draw a red 3 from the remining deck if all the red cards have been taken out? The probability would be 0 for the red 3.

    The probability of drawing a face card from the remaining deck after the red ones have been taken out would be 6/26. There are 26 cards left in the remaining deck which are all black. There are 6 faces cards in that deck. 6/26=3/13.

    Being that is the way you received the problem, it is very ill-posed.
    jstrike's Avatar
    jstrike Posts: 418, Reputation: 44
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    #9

    Apr 17, 2008, 06:56 PM
    I had a question once on a test where the professor took two paragraphs to describe the make up of names, addresses and phone numbers in a phone book and then asked what the probability was of finding an unlisted number for a specific area of the city. The answer was 0 because there are no unlisted phone numbers in the phone book but I saw most of the class trying to figure it out.

    Incidentally, wouldn't the probability of drawing a face card be 6/25 (24%) because you've already drawn one card out?
    CharlieGJr's Avatar
    CharlieGJr Posts: 2, Reputation: -1
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    #10

    May 22, 2008, 08:10 PM
    If the remaining cardfs are red and you pick one without replacing it, you should have 25 left over. Now if you only have 25 cards left and there are only 2 threes and 6 face cards then it should be 2/25 = .08 + 6/25 = .24 . The answer should be 32% if I read it correctly if not then it will be 0.
    morgaine300's Avatar
    morgaine300 Posts: 6,561, Reputation: 276
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    #11

    May 22, 2008, 09:53 PM
    What is the probability that a red 3 is selected and a face3 card is selected?
    Here's a darn good question:

    Does this mean what is the probability that a red 3 is selected as the first, AND the probability that a face card is selected as the second card? As in two different questions and two different probabilities.

    Or does it mean what is the probability that a red 3 is selected as the first AND the face card selected as the second, all in one probability? i.e. as in a two-step experiment and the probability of an outcome of that whole experiment. (In which case the probability is zero cause the first step can't even happen.)

    If that makes sense.

    It's an extremely badly worded question and personally I think you should ask your instructor about it.

    As for focusing on the math question... first of all, if someone is having trouble understanding the question due to a typo, then explaining how to edit is a perfectly legit thing to say. Second, sometimes people who post that type of info don't have an answer to the actual question -- they are just trying to be helpful about how to do things on the site.
    amber-doo's Avatar
    amber-doo Posts: 34, Reputation: 4
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    #12

    May 28, 2008, 01:56 PM
    It sounds like they want to know what the probability of both a red 3 and a face card being picked... that answer would be 0 because there is no way for there to be a red 3. If they want to know the probability of those events happening separately then you would have to know in what order the cards were selected. You would have to be asked the probability of the face card being chosen first or second.

    The probability of the face card being chosen first would be 6/26=23.076%
    The probability of the face card being chosen second, given the first card was not a face card would be 6/25=24%

    BUT, I think the question is the probability of both events happening, that is 0.
    jstrike's Avatar
    jstrike Posts: 418, Reputation: 44
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    #13

    May 28, 2008, 02:21 PM
    Quote Originally Posted by amber-doo
    It sounds like they want to know what the probability of both a red 3 and a face card being picked....that answer would be 0 because there is no way for there to be a red 3.
    The question is poorly worded so it's hard to understand

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