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Psyche90 · Apr 18, 2008, 12:58 PM

I missed a few pre-calc classes and I don't understand how to solve for theta. How do I do this problem??
heeeeelp please

2sin^2(theta)=3(1-cos(theta))^2

galactus · Apr 18, 2008, 01:37 PM

$2sin^{2}{\theta}=3(1-cos{\theta})^{2}$

Use $sin^{2}{\theta}=1-cos^{2}{\theta}$

$2-2cos^{2}{\theta}=3-6cos{\theta}+3cos^{2}{\theta}$

$5cos^{2}{\theta}-6cos{\theta}+1=0$

Now, you can let $u=cos{\theta}$

$5u^{2}-6u+1=0$

Now, solve the quadratic and resub.