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    Stephen09's Avatar
    Stephen09 Posts: 11, Reputation: 0
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    #1

    Sep 17, 2008, 05:47 PM
    Need PHYSICS guru to show me how
    If anyone reads this in the next hour or so and you can help with physics PLEASE RESPOND! THANKS! (ill tell you the problem when you respond)
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #2

    Sep 17, 2008, 05:51 PM
    Go for it..
    ballengerb1's Avatar
    ballengerb1 Posts: 27,378, Reputation: 2280
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    #3

    Sep 17, 2008, 05:54 PM
    Stephen, you got a response in 4 minutes and now you are AWOL. Normally folks tell us their question and those qualified will respond. What grade are you in and where?
    Stephen09's Avatar
    Stephen09 Posts: 11, Reputation: 0
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    #4

    Sep 17, 2008, 06:12 PM
    I'm a senior in physics
    Stephen09's Avatar
    Stephen09 Posts: 11, Reputation: 0
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    #5

    Sep 17, 2008, 06:15 PM
    Thanks for the concern guys... here it is:

    A descent vehicle landing on the moon has a vertical velocity toward the surface of the moon of 23.5m/s. At the same time, it has a horizontal velocity of 56m/s.

    a) At what speed does the vehicle move along its descent path?

    b) At what angle with the vertical is its path?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #6

    Sep 17, 2008, 06:29 PM
    This is simple vector addition, which is basic trigonometry:

    Just take your 2 vectors and use them as the 2 short sides of a right angled triangle. a) is the length of the hypotenuse and b) is the corresponding angle.
    Stephen09's Avatar
    Stephen09 Posts: 11, Reputation: 0
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    #7

    Sep 17, 2008, 06:35 PM
    So for part B your saying to use a tangent formula or what?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #8

    Sep 17, 2008, 06:37 PM
    Quote Originally Posted by Stephen09
    so for part B your saying to use a tangent formula or what?
    From doing it in my head, it looks like you'll need to use cos(x) = adj/hyp, but you should check that.
    Stephen09's Avatar
    Stephen09 Posts: 11, Reputation: 0
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    #9

    Sep 17, 2008, 06:41 PM
    With the adjacent being 56?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #10

    Sep 17, 2008, 06:49 PM
    Quote Originally Posted by Stephen09
    with the adjacent being 56?
    No, you want the angle to the vertical, so you want the vertical to be adjacent.
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    Stephen09 Posts: 11, Reputation: 0
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    #11

    Sep 17, 2008, 07:13 PM
    If that were so it would be cos(23.5/60) and that ends up being .99 degrees...
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #12

    Sep 17, 2008, 07:15 PM
    Quote Originally Posted by Stephen09
    it would be cos(23.5/60)
    No it wouldn't. How did you get that?
    ddpatel's Avatar
    ddpatel Posts: 1, Reputation: 1
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    #13

    Sep 19, 2008, 11:10 AM
    Quote Originally Posted by Stephen09
    thanks for the concern guys... here it is:

    a descent vehicle landing on the moon has a vertical velocity toward the surface of the moon of 23.5m/s. At the same time, it has a horizontal velocity of 56m/s.

    a) At what speed does the vehicle move along its descent path?

    b) At what angle with the vertical is its path?
    bbbb
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #14

    Sep 20, 2008, 03:12 AM

    Wait a sec. The vertical is 23.5 and horizontal is 56. I think that tangent rule applies?

    Anyway, that's what I would have done, without using my answer from (a) to avoid errors carried forward.
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