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    Eelarch's Avatar
    Eelarch Posts: 116, Reputation: 3
    Junior Member
    		  
    #1

    Jan 28, 2010, 12:50 PM
    Parralell equation i have working i that may or may not be right I'm not sure.
    kx - 3y + 7 = 0 is parallel to the line with gradient 5, what is the value for k?


    Y=MX+C

    KX-3y+7=0
    3y=5X+7
    Y=(5/3)X + 7

    K=5/3
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
    		  
    #2

    Jan 29, 2010, 09:06 AM

    No, you didn't understand well the method to do it.

    Yes, you need to put it in the form of Y = mX + C

    kx - 3y + 7 = 0

    Adding y on both sides;

    kx + 7 = 3y

    Rearrange;

    3y = kx + 7

    Divide both sides by 3;



    Now, it's in the form Y = mX + C.

    Since m is the gradient, and is 5, hence;

    m = 5 = k/3

    Can you solve it now?
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