 Ask Remember Me? wateverlala Posts: 2, Reputation: 1 New Member #1 Oct 25, 2007, 05:53 PM
More algebra 1
Armando and drew do volunteer work at an animal shelter. Drew worked 3 more hours than armando, and together they worked more than 27 hours. What is the least number of hours each worked?:confused: :confused: :eek: sGt HarDKorE Posts: 656, Reputation: 98 Senior Member #2 Oct 25, 2007, 06:20 PM
Lets have Drew = x
and Armando = y

y=x+3
x+y>27

x+(x+3)=27

2x+3=27
2x=24
x=12

12+y=27
y=15

The least amount they worked was

x>12
y>15

because they worked more than 27 hours so it has to be greater than a total of 27

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