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    Toaster's Avatar
    Toaster Posts: 9, Reputation: 1
    New Member
    		  
    #1

    Aug 9, 2009, 05:46 PM
    Log Equation Check
    Ok my [math] tags failed completely so were going to do this the old school way.

    Im nearing my way through the end of the log chapter in my math book, but I just want to check to see if I've got this one right (because I'm not so sure it is).

    Here's the equation and what I've done.

    log_2(2m+4) - log_2(m-1)=3

    using the properties of logs I did

    log_2(2m+4/m-1)=3

    2^3=(2m+4/m-1)

    Here's where it gets sketchy..

    (m-1)8=(m-1)2m+4/m-1.. the m-1's cancel out

    8m-8=2m+4
    6m/6=12/6
    m=2

    Ok so I got an answer so that's something :P... its been a while since I've dealt with fractional equations so let me know if this is right or if I'm even close/point me in the right direction.

    Thanks again!

    Trevor
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #2

    Aug 9, 2009, 05:51 PM
    You got it. Just plug it back in to check, but that's right.
    Toaster's Avatar
    Toaster Posts: 9, Reputation: 1
    New Member
    		  
    #3

    Aug 9, 2009, 05:53 PM

    Awesome! Thanks for the feedback!
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