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    qwertyuioop's Avatar
    qwertyuioop Posts: 87, Reputation: 1
    Junior Member
     
    #1

    Jun 14, 2012, 06:31 AM
    intercepts
    how do I dp this?
    for the equation 5x-3y=-30 I have 2 find x and y intercepts
    5x-3y=-30 so let x be 0
    0-3y=-30 and how do u do the last step for x and y?
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
    Expert
     
    #2

    Jun 14, 2012, 06:41 AM
    Quote Originally Posted by qwertyuioop View Post
    how do i dp this??
    for the equation 5x-3y=-30 i have 2 find x and y intercepts
    5x-3y=-30 so let x be 0
    0-3y=-30 and how do u do the last step for x and y??
    You have:
    0 - 3y = -30

    You're almost there - just solve for y. Start by adding '3y' to both sides:

    0-3y+3y = -30 +3y
    0 = -30 +3y

    Add 30 to both sides:

    0 + 30 = -30 + 3y + 30
    30 = 3y

    Divide both sides by 3:

    30/3 = 3y/3
    10 = y

    That's the y-intercept. Do the same process to find the x-intercept by setting y=0 in that original equation and solve for x.
    qwertyuioop's Avatar
    qwertyuioop Posts: 87, Reputation: 1
    Junior Member
     
    #3

    Jun 14, 2012, 06:44 AM
    Awsome thanks I get it now!!

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