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    wlfarr8's Avatar
    wlfarr8 Posts: 1, Reputation: 1
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    #1

    Nov 24, 2017, 04:34 PM
    How many four digit odd numbers can be formed using only the digits 0, 3, 2, 7, and 5
    I would like to know how to start solving this problem. Please provide step by step instructions in simplified form.
    ebaines's Avatar
    ebaines Posts: 12,132, Reputation: 1307
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    #2

    Dec 2, 2017, 12:58 PM
    You need to specify whether digits may be repeated or not - for example is 3333 an allowable number?

    I suggest thinking first about the last digit, which must be a 3, 5 or 7. Hence there are three possible choices for that digit. Then the first digit: it cannot be zero, so there are either four possible choices (if digits may be repeated) or three (if not). Then consider the second and third digits - how many choices are there for each of them?

    Post back with your attempt and we'll check it for you.

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