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    tony39531's Avatar
    tony39531 Posts: 1, Reputation: 1
    New Member

    Dec 17, 2007, 08:20 AM
    How do I solve a word dilemma using quadratic equation
    I have worked for days on this and went to every website and test I could find but cannot wrap my brain around this.

    Word problems give me great difficulty and I am supposed to construct a quadratic equation for this. I'd really appreciate some help.

    if a retailer spends $48 to purchase some items and two of them were broken in the store and the remaining mugs were sold for $3 above the cost of the mugs, profit was $22

    I have to construct an equation to solve for the number of mugs that were originally purchased.

    I think the formula is supposed to be ax (sq) +bx+c=0 but I have no idea how to plug in the numbers or if this is a proper formula. I have worked for days and even looked at wikipedia and can't get it. Please help :confused:
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
    Ultra Member

    Dec 17, 2007, 05:52 PM
    Profit = Revenue - Cost.

    The Profit is $22. The cost is $48.

    Now, the trickiest part. After 2 are broken, the mugs sell for $3 more, a piece, then what they paid for them.

    Each mug cost 48/n dollars. There are n-2 of them top sell.

    The quadratic is

    Solve away. One solution will be negative, therefore, erroneous.

    Factor, use the quadratic formula, complete the square. Whatever.

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