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maramfaith24 · Jan 9, 2011, 03:26 PM

I'm not looking for answer, just the step to finish the equation and figure out which conic section it forms?

Here's the equation: x^2=y^2+9.

I think I start by putting the equation into y=mx+b form, so it can be graph on a graphing calculator.

But I can't figure out how it's going to look in the end, can you help?

galactus · Jan 9, 2011, 03:44 PM

How could you write it in y=mx+b form? y=mx+b is the slope intercept form of a line.

This has nothing to do with a line.

I think you are just referring to solving it for y so you can graph it.

Yes, you can do that. $y=\pm \sqrt{x^{2}-9}$

To solve it without graphing, rewrite it as:

$x^{2}-y^{2}=9$

Divide by 9:

$\frac{x^{2}}{9}-\frac{y^{2}}{9}=1$

This is a hyperbola with vertices at (-3,0) and (3,0)

maramfaith24 · Jan 9, 2011, 04:35 PM

So would re-write be the easier way of the two? I'm sorry, I am just really conused. I'm an online student, so if I don't understand something.. This website is normally where I come.

maramfaith24 · Jan 9, 2011, 04:49 PM

The way my teacher wants my to do it, is to first solve or y.

galactus · Jan 10, 2011, 05:42 AM

I already solved it for y.

Graph that in your calculator.

Don't forget the positive and negative or you'll just get one side.

Graph $y=\sqrt{x^{2}-9}$ and $y=-\sqrt{x^{2}-9}$