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jwtear · Dec 26, 2009, 02:49 AM

Here is shown in fig
Some text not shown in fig .
A women sitting in a train pours two cups,one 10 minute after other ,the train is moving in,,

Unknown008 · Dec 26, 2009, 03:48 AM

It's simple.

Let's say at time 0 minutes, the woman pours the first cup. Distance up to now is zero. After ten minutes, the second cup is poured. What distance did the train travel during that time?

Use the velocity, distance, time formula: $Distance\ =\ Speed\ \times\ Time$

jwtear · Dec 28, 2009, 12:25 AM

I knew it before but its result 200m where the answer is 12.000 m .

Unknown008 · Dec 28, 2009, 07:08 AM

Ah, you didn't pay attention to the units.

$Distance\ = \ 20ms^{-1}\ \times 10\ min = \ 20m\cancel{s^{-1}}\ \times (10 \times 60) \cancel{s} = 12\ 000 m$

galactus · Jan 1, 2010, 04:34 PM

Relativity problem.

Consider the Tolman-Bondi-de Sitter metric, given by $ds^{2}=dt^{2}-e^{-2{\Psi}(t,r)}dr^{2}-R^{2}(t,r)d{\theta}^{2}-R^{2}(t,r)sin^{2}{\theta}d{\phi}^{2}$ .

This metric arises in the study of spherical dust with a cosmological constant. Find the Ricci rotation coefficients for this metric.

:):confused:;)

Unknown008 · Jan 1, 2010, 10:50 PM

Meanie galactus :p

I don't even understand that, lol!

And by the way, love your new sig and avy. It's strange though, your sig. With simpler variables, it should be zero, but that's not the case.

galactus · Jan 2, 2010, 04:56 AM

Ha Ha. I just done that for wackiness and to have fun:);)

I do not understand it. I got it out of a book on Relativity that I have.