Help me please.

nyc123rr · Aug 1, 2012, 01:20 PM

for a group of four men , the probability distribution for the number x who live through the next year is as given in the accompanying table. Find out the mean and the standard deviation
x | p(x)
0 | 0.05
1 | 0.15
2 | 0.45
3 | 0.25
4 | 0.10

ebaines · Aug 1, 2012, 02:29 PM

Mean is found by applying

$<br /> \mu = \sum_{i=1} ^N p_i x_i <br />$

The standard deviation is found from:

$<br /> \sigma = \sqrt{ \sum_{i=1} ^N p_i (x_i -\mu)^2}<br />$

Take a shot at this and post back what you get.

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