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    ilovemattc's Avatar
    ilovemattc Posts: 2, Reputation: 1
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    #1

    Mar 19, 2009, 06:33 PM
    Graph parabola- opening to the side?
    (y+3)^2=-1(x+1) , list vertex, focus, directrix.. I know the formulas I just don't understand how to graph it and find the directrix to these kinds
    Perito's Avatar
    Perito Posts: 3,139, Reputation: 150
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    #2

    Mar 19, 2009, 08:15 PM

    Do you know how to find the vertex, focus, directrix, etc? That's where to start.

    Alternately, you simply pick a value for x and calculate y, then plot one point. Continue doing that until the graph is finished. That's probably not what your teacher wants you to do, however.

    Put the equation into a form where you can recognize the vertex, focux, etc. Then extract those parts of the formula and graph from that.
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #3

    Mar 20, 2009, 10:55 AM
    Use this as a guideline:

    https://www.askmehelpdesk.com/math-s...la-330673.html

    If you get stuck, let us know. Just solve your equation for y and then graph it.
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