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Donnanc31986 · Jun 28, 2007, 06:57 PM

I have to find the slope-intercept of an equation...

1. slope=2 passes through (1,5)...

2. passes through (-1,-5) and (3,2)

3. passes through (0,3) and is perpendicular to a line whose equation is y-7x=4?

galactus · Jun 29, 2007, 04:09 AM

i have to find the slope-intercept of an equation...

1. slope=2 passes through (1,5)...

Everything is given. Slope-intercept form is y=mx+b. You have x,y,and m. Plug those in and solve for b.

2. passes through (-1,-5) and (3,2)

Use the definition of slope, $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ to find m
You have x and y. Proceed as in #1.

3. passes through (0,3) and is perpendicular to a line whose equation is y-7x=4?

Solve y-7x=4 for y. It'll be in y=mx+b form. You can easily see what the slope is. The slope of the perp. Line will be the negative reciprocal of that. You have x and y, proceed as before.