Peachs Posts: 3, Reputation: 1 New Member #1 Apr 14, 2007, 11:39 AM
Finite Math - Probability
Every day Aaron, Bebe, and Cindy eat a piece of fruit for lunch. Aaron will eat an apple, banana, peach or orange with equal likelihood. Bebe will eat an apple, banana, or mango with 50% likelihood for an apple, 30% for a banana, and 20% for a mango. Cindy will eat either an apple or banana with equal likelihood. What is the probability that they all eat the same kind of fruit for lunch today?
 Capuchin Posts: 5,255, Reputation: 656 Uber Member #2 Apr 14, 2007, 11:53 AM
so you are looking for:

(A apple * B apple * C apple) + (A banana + B banana + C banana)

this is the probability that all of them will eat an apple plus the probability that all of them will eat a banana.

 Peachs Posts: 3, Reputation: 1 New Member #3 Apr 14, 2007, 12:04 PM
Originally Posted by Capuchin
so you are looking for:

(A apple * B apple * C apple) + (A banana + B banana + C banana)

this is the probability that all of them will eat an apple plus the probability that all of them will eat a banana.

 Capuchin Posts: 5,255, Reputation: 656 Uber Member #4 Apr 14, 2007, 12:07 PM
I told you how to work it out, you just need to put in the numbers from your question!
 Peachs Posts: 3, Reputation: 1 New Member #5 Apr 14, 2007, 12:21 PM
(.50*.30*.20) + (1+1+1) = .03 +3 = 3.03
 galactus Posts: 2,271, Reputation: 282 Ultra Member #6 Apr 14, 2007, 01:17 PM
Originally Posted by Peachs
(.50*.30*.20) + (1+1+1) = .03 +3 = 3.03
Obviously not. How can you have a probability greater than 1?
 Capuchin Posts: 5,255, Reputation: 656 Uber Member #7 Apr 14, 2007, 01:58 PM
Reread your notes, then have another go, I've done the hard bit for you.

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